What are the solutions to the equation 2x^2-16x+26=0 ?

The solutions to the equation 2x^2-16x+26=0 are x=4+sqrt(3),x=4-sqrt(3)

Find the zeros of 2x^2-16x+26=0

The zeros of 2x^2-16x+26=0 are x=4+sqrt(3),x=4-sqrt(3)

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2 x^{2} - 16 x + 26 = 0

x = 4 + 3, x = 4 - 3

Decimal Notation

x = 5.73205 \dots, x = 2.26794 \dots

Solution steps

2 x^{2} - 16 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 2 \cdot 26}{2 \cdot 2}

(- 16)^{2} - 4 \cdot 2 \cdot 26 = 43

x_{1, 2} = \frac{- ( - 16 ) \pm 4 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 3}{2 \cdot 2}, x_{2} = \frac{- ( - 16 ) - 4 3}{2 \cdot 2}

x = \frac{- ( - 16 ) + 4 3}{2 \cdot 2} : 4 + 3

x = \frac{- ( - 16 ) - 4 3}{2 \cdot 2} : 4 - 3

The solutions to the quadratic equation are:

x = 4 + 3, x = 4 - 3

10 m^{2} + 8 m + 3 = 0

- (x + 3)^{2} + 5 = 0

(x + 2)^{2} - 3 = 4 x

y, x^{2} y^{2} - 2 x = 3

4 x^{2} + 2 x + 7

What are the solutions to the equation 2x^2-16x+26=0 ?
The solutions to the equation 2x^2-16x+26=0 are x=4+sqrt(3),x=4-sqrt(3)
Find the zeros of 2x^2-16x+26=0
The zeros of 2x^2-16x+26=0 are x=4+sqrt(3),x=4-sqrt(3)