What are the solutions to the equation -(x+3)^2+5=0 ?

The solutions to the equation -(x+3)^2+5=0 are x=sqrt(5)-3,x=-sqrt(5)-3

Find the zeros of -(x+3)^2+5=0

The zeros of -(x+3)^2+5=0 are x=sqrt(5)-3,x=-sqrt(5)-3

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- (x + 3)^{2} + 5 = 0

x = 5 - 3, x = - 5 - 3

Decimal Notation

x = - 0.76393 \dots, x = - 5.23606 \dots

Solution steps

- (x + 3)^{2} + 5 = 0

Move

5

to the right side

- (x + 3)^{2} = - 5

Divide both sides by

- 1

(x + 3)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 5 : x = 5 - 3

Solve

x + 3 = - 5 : x = - 5 - 3

The solutions to the quadratic equation are:

x = 5 - 3, x = - 5 - 3

(x + 2)^{2} - 3 = 4 x

y, x^{2} y^{2} - 2 x = 3

4 x^{2} + 2 x + 7

x^{2} - 4 x - 5 = 16

x^{2} - 2 x - 8

What are the solutions to the equation -(x+3)^2+5=0 ?
The solutions to the equation -(x+3)^2+5=0 are x=sqrt(5)-3,x=-sqrt(5)-3
Find the zeros of -(x+3)^2+5=0
The zeros of -(x+3)^2+5=0 are x=sqrt(5)-3,x=-sqrt(5)-3