What are the solutions to the equation -12x^2+48x=0 ?

The solutions to the equation -12x^2+48x=0 are x=0,x=4

Find the zeros of -12x^2+48x=0

The zeros of -12x^2+48x=0 are x=0,x=4

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- 12 x^{2} + 48 x = 0

x = 0, x = 4

Solution steps

- 12 x^{2} + 48 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

4 8^{2} - 4 (- 12) \cdot 0 = 48

x_{1, 2} = \frac{- 48 \pm 48}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- 48 + 48}{2 ( - 12 )}, x_{2} = \frac{- 48 - 48}{2 ( - 12 )}

x = \frac{- 48 + 48}{2 ( - 12 )} : 0

x = \frac{- 48 - 48}{2 ( - 12 )} : 4

The solutions to the quadratic equation are:

x = 0, x = 4

14 x^{2} - 5 = 33 x

- 2 x^{2} - 20 x - 6

4 d^{2} + 17 d + 10 = - d^{2}

15 - x^{2} = - 14

2 x^{2} - 26 x = - 3 x^{2} - 7 x - 18

What are the solutions to the equation -12x^2+48x=0 ?
The solutions to the equation -12x^2+48x=0 are x=0,x=4
Find the zeros of -12x^2+48x=0
The zeros of -12x^2+48x=0 are x=0,x=4