What are the solutions to the equation 14x^2-5=33x ?

The solutions to the equation 14x^2-5=33x are x= 5/2 ,x=-1/7

Find the zeros of 14x^2-5=33x

The zeros of 14x^2-5=33x are x= 5/2 ,x=-1/7

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14 x^{2} - 5 = 33 x

x = \frac{5}{2}, x = - \frac{1}{7}

Decimal Notation

x = 2.5, x = - 0.14285 \dots

Solution steps

14 x^{2} - 5 = 33 x

Move

33 x

to the left side

14 x^{2} - 5 - 33 x = 0

Write in the standard form

a x^{2} + b x + c = 0

14 x^{2} - 33 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 33 ) \pm ( - 33 ) ^{2} - 4 \cdot 14 ( - 5 )}{2 \cdot 14}

(- 33)^{2} - 4 \cdot 14 (- 5) = 37

x_{1, 2} = \frac{- ( - 33 ) \pm 37}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- ( - 33 ) + 37}{2 \cdot 14}, x_{2} = \frac{- ( - 33 ) - 37}{2 \cdot 14}

x = \frac{- ( - 33 ) + 37}{2 \cdot 14} : \frac{5}{2}

x = \frac{- ( - 33 ) - 37}{2 \cdot 14} : - \frac{1}{7}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{1}{7}

- 2 x^{2} - 20 x - 6

4 d^{2} + 17 d + 10 = - d^{2}

15 - x^{2} = - 14

2 x^{2} - 26 x = - 3 x^{2} - 7 x - 18

(6 x - 3) (- x + 3) = 0

What are the solutions to the equation 14x^2-5=33x ?
The solutions to the equation 14x^2-5=33x are x= 5/2 ,x=-1/7
Find the zeros of 14x^2-5=33x
The zeros of 14x^2-5=33x are x= 5/2 ,x=-1/7