What are the solutions to the equation -7x^2+5x+3=0 ?

The solutions to the equation -7x^2+5x+3=0 are x=-(-5+sqrt(109))/(14),x=(5+sqrt(109))/(14)

Find the zeros of -7x^2+5x+3=0

The zeros of -7x^2+5x+3=0 are x=-(-5+sqrt(109))/(14),x=(5+sqrt(109))/(14)

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- 7 x^{2} + 5 x + 3 = 0

x = - \frac{- 5 + 109}{14}, x = \frac{5 + 109}{14}

Decimal Notation

x = - 0.38859 \dots, x = 1.10287 \dots

Solution steps

- 7 x^{2} + 5 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 7 ) \cdot 3}{2 ( - 7 )}

5^{2} - 4 (- 7) \cdot 3 = 109

x_{1, 2} = \frac{- 5 \pm 109}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 5 + 109}{2 ( - 7 )}, x_{2} = \frac{- 5 - 109}{2 ( - 7 )}

x = \frac{- 5 + 109}{2 ( - 7 )} : - \frac{- 5 + 109}{14}

x = \frac{- 5 - 109}{2 ( - 7 )} : \frac{5 + 109}{14}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 109}{14}, x = \frac{5 + 109}{14}

2 x^{2} + 20 - 7 x = - 2 x

x^{2} + 4 x - 1

x^{2} + 4 x + 9

x^{2} + 4 x + 6

n, s = \frac{n ( n + 1 )}{2}

What are the solutions to the equation -7x^2+5x+3=0 ?
The solutions to the equation -7x^2+5x+3=0 are x=-(-5+sqrt(109))/(14),x=(5+sqrt(109))/(14)
Find the zeros of -7x^2+5x+3=0
The zeros of -7x^2+5x+3=0 are x=-(-5+sqrt(109))/(14),x=(5+sqrt(109))/(14)