What are the solutions to the equation roots s^2+4s+4 ?

The solutions to the equation roots s^2+4s+4 are s=-2

Find the zeros of roots s^2+4s+4

The zeros of roots s^2+4s+4 are s=-2

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roots

s^{2} + 4 s + 4

s = - 2

Solution steps

s^{2} + 4 s + 4

The roots are the intercepts with the x-axis

(y = 0)

s^{2} + 4 s + 4 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

s_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

s = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

s = - 2

The solution to the quadratic equation is:

s = - 2

x^{2} + \frac{2}{3} x + \frac{1}{3} = 0

- 5 x^{2} + 20 x - 15 = 0

15 x^{2} - 29 x + 8 = - 4

1.25 x^{2} = 15 x

12 x^{2} - 312 x + 1512 = 0

What are the solutions to the equation roots s^2+4s+4 ?
The solutions to the equation roots s^2+4s+4 are s=-2
Find the zeros of roots s^2+4s+4
The zeros of roots s^2+4s+4 are s=-2