What are the solutions to the equation -16t^2-20t+700=0 ?

The solutions to the equation -16t^2-20t+700=0 are t=-(5(1+sqrt(113)))/8 ,t=(5(sqrt(113)-1))/8

Find the zeros of -16t^2-20t+700=0

The zeros of -16t^2-20t+700=0 are t=-(5(1+sqrt(113)))/8 ,t=(5(sqrt(113)-1))/8

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- 16 t^{2} - 20 t + 700 = 0

t = - \frac{5 ( 1 + 113 )}{8}, t = \frac{5 ( 113 - 1 )}{8}

Decimal

t = - 7.26884 \dots, t = 6.01884 \dots

Solution steps

- 16 t^{2} - 20 t + 700 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 ( - 16 ) \cdot 700}{2 ( - 16 )}

(- 20)^{2} - 4 (- 16) \cdot 700 = 20113

t_{1, 2} = \frac{- ( - 20 ) \pm 20 113}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- ( - 20 ) + 20 113}{2 ( - 16 )}, t_{2} = \frac{- ( - 20 ) - 20 113}{2 ( - 16 )}

t = \frac{- ( - 20 ) + 20 113}{2 ( - 16 )} : - \frac{5 ( 1 + 113 )}{8}

t = \frac{- ( - 20 ) - 20 113}{2 ( - 16 )} : \frac{5 ( 113 - 1 )}{8}

The solutions to the quadratic equation are:

t = - \frac{5 ( 1 + 113 )}{8}, t = \frac{5 ( 113 - 1 )}{8}

10 c^{2} + 9 c - 1 = 6 c^{2}

- 2 x^{2} + 16 x - 3 = 0

3 x^{2} + 2 x - 1

3 (x + 7)^{2} - 2 = 22

x = 13 a^{2}

What are the solutions to the equation -16t^2-20t+700=0 ?
The solutions to the equation -16t^2-20t+700=0 are t=-(5(1+sqrt(113)))/8 ,t=(5(sqrt(113)-1))/8
Find the zeros of -16t^2-20t+700=0
The zeros of -16t^2-20t+700=0 are t=-(5(1+sqrt(113)))/8 ,t=(5(sqrt(113)-1))/8