What are the solutions to the equation 10c^2+9c-1=6c^2 ?

The solutions to the equation 10c^2+9c-1=6c^2 are c=(-9+sqrt(97))/8 ,c=(-9-sqrt(97))/8

Find the zeros of 10c^2+9c-1=6c^2

The zeros of 10c^2+9c-1=6c^2 are c=(-9+sqrt(97))/8 ,c=(-9-sqrt(97))/8

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10 c^{2} + 9 c - 1 = 6 c^{2}

c = \frac{- 9 + 97}{8}, c = \frac{- 9 - 97}{8}

Decimal Notation

c = 0.10610 \dots, c = - 2.35610 \dots

Solution steps

10 c^{2} + 9 c - 1 = 6 c^{2}

Move

6 c^{2}

to the left side

4 c^{2} + 9 c - 1 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

9^{2} - 4 \cdot 4 (- 1) = 97

c_{1, 2} = \frac{- 9 \pm 97}{2 \cdot 4}

Separate the solutions

c_{1} = \frac{- 9 + 97}{2 \cdot 4}, c_{2} = \frac{- 9 - 97}{2 \cdot 4}

c = \frac{- 9 + 97}{2 \cdot 4} : \frac{- 9 + 97}{8}

c = \frac{- 9 - 97}{2 \cdot 4} : \frac{- 9 - 97}{8}

The solutions to the quadratic equation are:

c = \frac{- 9 + 97}{8}, c = \frac{- 9 - 97}{8}

- 2 x^{2} + 16 x - 3 = 0

3 x^{2} + 2 x - 1

3 (x + 7)^{2} - 2 = 22

x = 13 a^{2}

27 - 4 x + x^{2}

What are the solutions to the equation 10c^2+9c-1=6c^2 ?
The solutions to the equation 10c^2+9c-1=6c^2 are c=(-9+sqrt(97))/8 ,c=(-9-sqrt(97))/8
Find the zeros of 10c^2+9c-1=6c^2
The zeros of 10c^2+9c-1=6c^2 are c=(-9+sqrt(97))/8 ,c=(-9-sqrt(97))/8