What are the solutions to the equation 2x^2+15x-7=2x ?

The solutions to the equation 2x^2+15x-7=2x are x= 1/2 ,x=-7

Find the zeros of 2x^2+15x-7=2x

The zeros of 2x^2+15x-7=2x are x= 1/2 ,x=-7

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2 x^{2} + 15 x - 7 = 2 x

x = \frac{1}{2}, x = - 7

Decimal Notation

x = 0.5, x = - 7

Solution steps

2 x^{2} + 15 x - 7 = 2 x

Move

2 x

to the left side

2 x^{2} + 13 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 (- 7) = 15

x_{1, 2} = \frac{- 13 \pm 15}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 13 + 15}{2 \cdot 2}, x_{2} = \frac{- 13 - 15}{2 \cdot 2}

x = \frac{- 13 + 15}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 13 - 15}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 7

- 3 x^{2} + 11 = 95

x^{2} + 31 = - 12 x

2 x^{2} + 16 x + 26

x, 2 x^{2} - 7 x + 3 = 0

4 x^{2} + 268 = - 72 x

What are the solutions to the equation 2x^2+15x-7=2x ?
The solutions to the equation 2x^2+15x-7=2x are x= 1/2 ,x=-7
Find the zeros of 2x^2+15x-7=2x
The zeros of 2x^2+15x-7=2x are x= 1/2 ,x=-7