What are the solutions to the equation 3m^2+10m+3=2m ?

The solutions to the equation 3m^2+10m+3=2m are m=(-4+sqrt(7))/3 ,m=-(4+sqrt(7))/3

Find the zeros of 3m^2+10m+3=2m

The zeros of 3m^2+10m+3=2m are m=(-4+sqrt(7))/3 ,m=-(4+sqrt(7))/3

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3 m^{2} + 10 m + 3 = 2 m

m = \frac{- 4 + 7}{3}, m = - \frac{4 + 7}{3}

Decimal Notation

m = - 0.45141 \dots, m = - 2.21525 \dots

Solution steps

3 m^{2} + 10 m + 3 = 2 m

Move

2 m

to the left side

3 m^{2} + 8 m + 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

8^{2} - 4 \cdot 3 \cdot 3 = 27

m_{1, 2} = \frac{- 8 \pm 2 7}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- 8 + 2 7}{2 \cdot 3}, m_{2} = \frac{- 8 - 2 7}{2 \cdot 3}

m = \frac{- 8 + 2 7}{2 \cdot 3} : \frac{- 4 + 7}{3}

m = \frac{- 8 - 2 7}{2 \cdot 3} : - \frac{4 + 7}{3}

The solutions to the quadratic equation are:

m = \frac{- 4 + 7}{3}, m = - \frac{4 + 7}{3}

x^{2} - 4 x + 2

x^{2} - 4 x + 200 = 0

2 (3 x^{2} - 1) = 6 x + 5 x

x^{2} + 12 x = 4

(2 x + 5) (x - 2) = 34

What are the solutions to the equation 3m^2+10m+3=2m ?
The solutions to the equation 3m^2+10m+3=2m are m=(-4+sqrt(7))/3 ,m=-(4+sqrt(7))/3
Find the zeros of 3m^2+10m+3=2m
The zeros of 3m^2+10m+3=2m are m=(-4+sqrt(7))/3 ,m=-(4+sqrt(7))/3