What are the solutions to the equation 5r^2-7r+4=6 ?

The solutions to the equation 5r^2-7r+4=6 are r=(7+sqrt(89))/(10),r=(7-sqrt(89))/(10)

Find the zeros of 5r^2-7r+4=6

The zeros of 5r^2-7r+4=6 are r=(7+sqrt(89))/(10),r=(7-sqrt(89))/(10)

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5 r^{2} - 7 r + 4 = 6

r = \frac{7 + 89}{10}, r = \frac{7 - 89}{10}

Decimal Notation

r = 1.64339 \dots, r = - 0.24339 \dots

Solution steps

5 r^{2} - 7 r + 4 = 6

Move

6

to the left side

5 r^{2} - 7 r - 2 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

(- 7)^{2} - 4 \cdot 5 (- 2) = 89

r_{1, 2} = \frac{- ( - 7 ) \pm 89}{2 \cdot 5}

Separate the solutions

r_{1} = \frac{- ( - 7 ) + 89}{2 \cdot 5}, r_{2} = \frac{- ( - 7 ) - 89}{2 \cdot 5}

r = \frac{- ( - 7 ) + 89}{2 \cdot 5} : \frac{7 + 89}{10}

r = \frac{- ( - 7 ) - 89}{2 \cdot 5} : \frac{7 - 89}{10}

The solutions to the quadratic equation are:

r = \frac{7 + 89}{10}, r = \frac{7 - 89}{10}

x^{2} + 4 x + 29

5 (m + n - 1) x^{2} + 4 (m - n) x + \frac{mn}{12} = 0

x^{2} - 7 x - 144 = 0

9 w^{2} - 27 w + 20 = 0

16 x^{2} - 25 x = - 9

What are the solutions to the equation 5r^2-7r+4=6 ?
The solutions to the equation 5r^2-7r+4=6 are r=(7+sqrt(89))/(10),r=(7-sqrt(89))/(10)
Find the zeros of 5r^2-7r+4=6
The zeros of 5r^2-7r+4=6 are r=(7+sqrt(89))/(10),r=(7-sqrt(89))/(10)