What are the solutions to the equation 2x^2-7x+5=10 ?

The solutions to the equation 2x^2-7x+5=10 are x=(7+sqrt(89))/4 ,x=(7-sqrt(89))/4

Find the zeros of 2x^2-7x+5=10

The zeros of 2x^2-7x+5=10 are x=(7+sqrt(89))/4 ,x=(7-sqrt(89))/4

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2 x^{2} - 7 x + 5 = 10

x = \frac{7 + 89}{4}, x = \frac{7 - 89}{4}

Decimal Notation

x = 4.10849 \dots, x = - 0.60849 \dots

Solution steps

2 x^{2} - 7 x + 5 = 10

Move

10

to the left side

2 x^{2} - 7 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 5) = 89

x_{1, 2} = \frac{- ( - 7 ) \pm 89}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 89}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 89}{2 \cdot 2}

x = \frac{- ( - 7 ) + 89}{2 \cdot 2} : \frac{7 + 89}{4}

x = \frac{- ( - 7 ) - 89}{2 \cdot 2} : \frac{7 - 89}{4}

The solutions to the quadratic equation are:

x = \frac{7 + 89}{4}, x = \frac{7 - 89}{4}

5 r^{2} - 7 r + 4 = 6

x^{2} + 4 x + 29

5 (m + n - 1) x^{2} + 4 (m - n) x + \frac{mn}{12} = 0

x^{2} - 7 x - 144 = 0

9 w^{2} - 27 w + 20 = 0

What are the solutions to the equation 2x^2-7x+5=10 ?
The solutions to the equation 2x^2-7x+5=10 are x=(7+sqrt(89))/4 ,x=(7-sqrt(89))/4
Find the zeros of 2x^2-7x+5=10
The zeros of 2x^2-7x+5=10 are x=(7+sqrt(89))/4 ,x=(7-sqrt(89))/4