What are the solutions to the equation x^2+2/3 x-1/9 =0 ?

The solutions to the equation x^2+2/3 x-1/9 =0 are x=(-1+sqrt(2))/3 ,x=-(1+sqrt(2))/3

Find the zeros of x^2+2/3 x-1/9 =0

The zeros of x^2+2/3 x-1/9 =0 are x=(-1+sqrt(2))/3 ,x=-(1+sqrt(2))/3

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x^{2} + \frac{2}{3} x - \frac{1}{9} = 0

x = \frac{- 1 + 2}{3}, x = - \frac{1 + 2}{3}

Decimal Notation

x = 0.13807 \dots, x = - 0.80473 \dots

Solution steps

x^{2} + \frac{2}{3} x - \frac{1}{9} = 0

Find Least Common Multiplier of

3, 9 : 9

Multiply by LCM=

9

x^{2} \cdot 9 + \frac{2}{3} x \cdot 9 - \frac{1}{9} \cdot 9 = 0 \cdot 9

Simplify

9 x^{2} + 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 ( - 1 )}{2 \cdot 9}

6^{2} - 4 \cdot 9 (- 1) = 62

x_{1, 2} = \frac{- 6 \pm 6 2}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 6 + 6 2}{2 \cdot 9}, x_{2} = \frac{- 6 - 6 2}{2 \cdot 9}

x = \frac{- 6 + 6 2}{2 \cdot 9} : \frac{- 1 + 2}{3}

x = \frac{- 6 - 6 2}{2 \cdot 9} : - \frac{1 + 2}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 2}{3}, x = - \frac{1 + 2}{3}

4 m^{2} - 15 m + 5 = - 3 m

2 x^{2} - 13 x + 3 = - 4 x

3 x^{2} + 24 x + 48 = - 108

2 x^{2} + 3 x - 20 = 0

x^{2} + \frac{3}{2} x - 3 = 0

What are the solutions to the equation x^2+2/3 x-1/9 =0 ?
The solutions to the equation x^2+2/3 x-1/9 =0 are x=(-1+sqrt(2))/3 ,x=-(1+sqrt(2))/3
Find the zeros of x^2+2/3 x-1/9 =0
The zeros of x^2+2/3 x-1/9 =0 are x=(-1+sqrt(2))/3 ,x=-(1+sqrt(2))/3