What are the solutions to the equation 2x^2-13x+3=-4x ?

The solutions to the equation 2x^2-13x+3=-4x are x=(9+sqrt(57))/4 ,x=(9-sqrt(57))/4

Find the zeros of 2x^2-13x+3=-4x

The zeros of 2x^2-13x+3=-4x are x=(9+sqrt(57))/4 ,x=(9-sqrt(57))/4

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2 x^{2} - 13 x + 3 = - 4 x

x = \frac{9 + 57}{4}, x = \frac{9 - 57}{4}

Decimal Notation

x = 4.13745 \dots, x = 0.36254 \dots

Solution steps

2 x^{2} - 13 x + 3 = - 4 x

Move

4 x

to the left side

2 x^{2} - 9 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 \cdot 3 = 57

x_{1, 2} = \frac{- ( - 9 ) \pm 57}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 57}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 57}{2 \cdot 2}

x = \frac{- ( - 9 ) + 57}{2 \cdot 2} : \frac{9 + 57}{4}

x = \frac{- ( - 9 ) - 57}{2 \cdot 2} : \frac{9 - 57}{4}

The solutions to the quadratic equation are:

x = \frac{9 + 57}{4}, x = \frac{9 - 57}{4}

3 x^{2} + 24 x + 48 = - 108

2 x^{2} + 3 x - 20 = 0

x^{2} + \frac{3}{2} x - 3 = 0

2 x^{2} - 9 x + 21 = 0

y, y^{2} - 3 x y + 5 x^{2} y = 13 + x y^{2}

What are the solutions to the equation 2x^2-13x+3=-4x ?
The solutions to the equation 2x^2-13x+3=-4x are x=(9+sqrt(57))/4 ,x=(9-sqrt(57))/4
Find the zeros of 2x^2-13x+3=-4x
The zeros of 2x^2-13x+3=-4x are x=(9+sqrt(57))/4 ,x=(9-sqrt(57))/4