What are the solutions to the equation 5y^2+7y-1=0 ?

The solutions to the equation 5y^2+7y-1=0 are y=(-7+sqrt(69))/(10),y=(-7-sqrt(69))/(10)

Find the zeros of 5y^2+7y-1=0

The zeros of 5y^2+7y-1=0 are y=(-7+sqrt(69))/(10),y=(-7-sqrt(69))/(10)

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5 y^{2} + 7 y - 1 = 0

y = \frac{- 7 + 69}{10}, y = \frac{- 7 - 69}{10}

Decimal Notation

y = 0.13066 \dots, y = - 1.53066 \dots

Solution steps

5 y^{2} + 7 y - 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

7^{2} - 4 \cdot 5 (- 1) = 69

y_{1, 2} = \frac{- 7 \pm 69}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- 7 + 69}{2 \cdot 5}, y_{2} = \frac{- 7 - 69}{2 \cdot 5}

y = \frac{- 7 + 69}{2 \cdot 5} : \frac{- 7 + 69}{10}

y = \frac{- 7 - 69}{2 \cdot 5} : \frac{- 7 - 69}{10}

The solutions to the quadratic equation are:

y = \frac{- 7 + 69}{10}, y = \frac{- 7 - 69}{10}

x, x^{2} + y^{2} + z^{2} = 16

2 x^{2} - 3 x - 15 = - 4 x

9 x = - x^{2} - 18

2 c^{2} - 10 c + 12 = 0

y^{2} - 10 y + 30 = 0

What are the solutions to the equation 5y^2+7y-1=0 ?
The solutions to the equation 5y^2+7y-1=0 are y=(-7+sqrt(69))/(10),y=(-7-sqrt(69))/(10)
Find the zeros of 5y^2+7y-1=0
The zeros of 5y^2+7y-1=0 are y=(-7+sqrt(69))/(10),y=(-7-sqrt(69))/(10)