What are the solutions to the equation 2x^2-3x-15=-4x ?

The solutions to the equation 2x^2-3x-15=-4x are x= 5/2 ,x=-3

Find the zeros of 2x^2-3x-15=-4x

The zeros of 2x^2-3x-15=-4x are x= 5/2 ,x=-3

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2 x^{2} - 3 x - 15 = - 4 x

x = \frac{5}{2}, x = - 3

Decimal Notation

x = 2.5, x = - 3

Solution steps

2 x^{2} - 3 x - 15 = - 4 x

Move

4 x

to the left side

2 x^{2} + x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 15) = 11

x_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 11}{2 \cdot 2}, x_{2} = \frac{- 1 - 11}{2 \cdot 2}

x = \frac{- 1 + 11}{2 \cdot 2} : \frac{5}{2}

x = \frac{- 1 - 11}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 3

9 x = - x^{2} - 18

2 c^{2} - 10 c + 12 = 0

y^{2} - 10 y + 30 = 0

18 x^{2} - 6 = 8 x

y, x^{2} + x y + y^{2} = 4

What are the solutions to the equation 2x^2-3x-15=-4x ?
The solutions to the equation 2x^2-3x-15=-4x are x= 5/2 ,x=-3
Find the zeros of 2x^2-3x-15=-4x
The zeros of 2x^2-3x-15=-4x are x= 5/2 ,x=-3