What are the solutions to the equation (3x-2)x=(5x-1)x ?

The solutions to the equation (3x-2)x=(5x-1)x are x=0,x=-1/2

Find the zeros of (3x-2)x=(5x-1)x

The zeros of (3x-2)x=(5x-1)x are x=0,x=-1/2

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(3 x - 2) x = (5 x - 1) x

x = 0, x = - \frac{1}{2}

Decimal Notation

x = 0, x = - 0.5

Solution steps

(3 x - 2) x = (5 x - 1) x

Move

(5 x - 1) x

to the left side

(3 x - 2) x - (5 x - 1) x = 0

Factor

(3 x - 2) x - (5 x - 1) x : - x (2 x + 1)

- x (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 1 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{2}

2 (x + 1)^{2} + 30 = 32

33 b = 10 - 7 b^{2}

12 x^{2} - 288 x + 1260 = 0

v, \frac{m v ^{2}}{r} = q v B

\frac{1}{6} z^{2} + \frac{4}{6} z = 2

What are the solutions to the equation (3x-2)x=(5x-1)x ?
The solutions to the equation (3x-2)x=(5x-1)x are x=0,x=-1/2
Find the zeros of (3x-2)x=(5x-1)x
The zeros of (3x-2)x=(5x-1)x are x=0,x=-1/2