What are the solutions to the equation 2q^2+10q-3=0 ?

The solutions to the equation 2q^2+10q-3=0 are q=(-5+sqrt(31))/2 ,q=-(5+sqrt(31))/2

Find the zeros of 2q^2+10q-3=0

The zeros of 2q^2+10q-3=0 are q=(-5+sqrt(31))/2 ,q=-(5+sqrt(31))/2

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2 q^{2} + 10 q - 3 = 0

q = \frac{- 5 + 31}{2}, q = - \frac{5 + 31}{2}

Decimal Notation

q = 0.28388 \dots, q = - 5.28388 \dots

Solution steps

2 q^{2} + 10 q - 3 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 (- 3) = 231

q_{1, 2} = \frac{- 10 \pm 2 31}{2 \cdot 2}

Separate the solutions

q_{1} = \frac{- 10 + 2 31}{2 \cdot 2}, q_{2} = \frac{- 10 - 2 31}{2 \cdot 2}

q = \frac{- 10 + 2 31}{2 \cdot 2} : \frac{- 5 + 31}{2}

q = \frac{- 10 - 2 31}{2 \cdot 2} : - \frac{5 + 31}{2}

The solutions to the quadratic equation are:

q = \frac{- 5 + 31}{2}, q = - \frac{5 + 31}{2}

3 x^{2} + 10 x + 9 = - 3 x + 5

(x + 36)^{2} - 38 = 251

5 x^{2} + 2 x - 3

r^{2} - r - 14 = 2 r

14 x^{2} - 36 x + 16 = 0

What are the solutions to the equation 2q^2+10q-3=0 ?
The solutions to the equation 2q^2+10q-3=0 are q=(-5+sqrt(31))/2 ,q=-(5+sqrt(31))/2
Find the zeros of 2q^2+10q-3=0
The zeros of 2q^2+10q-3=0 are q=(-5+sqrt(31))/2 ,q=-(5+sqrt(31))/2