What are the solutions to the equation x^2-12x+c=0 ?

The solutions to the equation x^2-12x+c=0 are x=6+sqrt(-c+36),x=6-sqrt(-c+36)

Find the zeros of x^2-12x+c=0

The zeros of x^2-12x+c=0 are x=6+sqrt(-c+36),x=6-sqrt(-c+36)

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x^{2} - 12 x + c = 0

x = 6 + - c + 36, x = 6 - - c + 36

Solution steps

x^{2} - 12 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

(- 12)^{2} - 4 \cdot 1 \cdot c : 2 36 - c

x_{1, 2} = \frac{- ( - 12 ) \pm 2 36 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 36 - c}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 36 - c}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 36 - c}{2 \cdot 1} : 6 + - c + 36

x = \frac{- ( - 12 ) - 2 36 - c}{2 \cdot 1} : 6 - - c + 36

The solutions to the quadratic equation are:

x = 6 + - c + 36, x = 6 - - c + 36

2 x^{2} - 5 x - 3

x^{2} + 2 x = 3

6 q^{2} + 10 q + 25 = 5 q^{2}

19 v^{2} - v - 2 = 4 v^{2}

2 x (x - 2) = 200

What are the solutions to the equation x^2-12x+c=0 ?
The solutions to the equation x^2-12x+c=0 are x=6+sqrt(-c+36),x=6-sqrt(-c+36)
Find the zeros of x^2-12x+c=0
The zeros of x^2-12x+c=0 are x=6+sqrt(-c+36),x=6-sqrt(-c+36)