What are the solutions to the equation roots 2x^2-5x-3 ?

The solutions to the equation roots 2x^2-5x-3 are x=3,x=-1/2

Find the zeros of roots 2x^2-5x-3

The zeros of roots 2x^2-5x-3 are x=3,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

2 x^{2} - 5 x - 3

x = 3, x = - \frac{1}{2}

Solution steps

2 x^{2} - 5 x - 3

The roots are the intercepts with the x-axis

(y = 0)

2 x^{2} - 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 3) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 2}

x = \frac{- ( - 5 ) + 7}{2 \cdot 2} : 3

x = \frac{- ( - 5 ) - 7}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{2}

x^{2} + 2 x = 3

6 q^{2} + 10 q + 25 = 5 q^{2}

19 v^{2} - v - 2 = 4 v^{2}

2 x (x - 2) = 200

(1 - x)^{2} = e^{3}

What are the solutions to the equation roots 2x^2-5x-3 ?
The solutions to the equation roots 2x^2-5x-3 are x=3,x=-1/2
Find the zeros of roots 2x^2-5x-3
The zeros of roots 2x^2-5x-3 are x=3,x=-1/2