What are the solutions to the equation roots 4x^2-4x+1 ?

The solutions to the equation roots 4x^2-4x+1 are x= 1/2

Find the zeros of roots 4x^2-4x+1

The zeros of roots 4x^2-4x+1 are x= 1/2

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roots

4 x^{2} - 4 x + 1

x = \frac{1}{2}

Solution steps

4 x^{2} - 4 x + 1

The roots are the intercepts with the x-axis

(y = 0)

4 x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

8 x^{2} = 56 x

- 10 x^{2} - 8 = - 8

16 r^{2} = 4 a^{2}

\frac{25}{6} x^{2} = \frac{8}{3}

9 x^{2} + 12 x + 11 = 6 x^{2}

What are the solutions to the equation roots 4x^2-4x+1 ?
The solutions to the equation roots 4x^2-4x+1 are x= 1/2
Find the zeros of roots 4x^2-4x+1
The zeros of roots 4x^2-4x+1 are x= 1/2