What are the solutions to the equation 2t^2-3t-10=0 ?

The solutions to the equation 2t^2-3t-10=0 are t=(3+sqrt(89))/4 ,t=(3-sqrt(89))/4

Find the zeros of 2t^2-3t-10=0

The zeros of 2t^2-3t-10=0 are t=(3+sqrt(89))/4 ,t=(3-sqrt(89))/4

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2 t^{2} - 3 t - 10 = 0

t = \frac{3 + 89}{4}, t = \frac{3 - 89}{4}

Decimal Notation

t = 3.10849 \dots, t = - 1.60849 \dots

Solution steps

2 t^{2} - 3 t - 10 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 10) = 89

t_{1, 2} = \frac{- ( - 3 ) \pm 89}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- ( - 3 ) + 89}{2 \cdot 2}, t_{2} = \frac{- ( - 3 ) - 89}{2 \cdot 2}

t = \frac{- ( - 3 ) + 89}{2 \cdot 2} : \frac{3 + 89}{4}

t = \frac{- ( - 3 ) - 89}{2 \cdot 2} : \frac{3 - 89}{4}

The solutions to the quadratic equation are:

t = \frac{3 + 89}{4}, t = \frac{3 - 89}{4}

y, 9 y^{2} = x (x - 3)^{2}

s^{2} + 1

5 m^{2} + 8 m - 51 = 2 m^{2}

- 4.9 t^{2} + t + 360 = - 4 t + 142

x^{2} + 16 x = 1555

What are the solutions to the equation 2t^2-3t-10=0 ?
The solutions to the equation 2t^2-3t-10=0 are t=(3+sqrt(89))/4 ,t=(3-sqrt(89))/4
Find the zeros of 2t^2-3t-10=0
The zeros of 2t^2-3t-10=0 are t=(3+sqrt(89))/4 ,t=(3-sqrt(89))/4