What are the solutions to the equation 5m^2+8m-51=2m^2 ?

The solutions to the equation 5m^2+8m-51=2m^2 are m=3,m=-17/3

Find the zeros of 5m^2+8m-51=2m^2

The zeros of 5m^2+8m-51=2m^2 are m=3,m=-17/3

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5 m^{2} + 8 m - 51 = 2 m^{2}

m = 3, m = - \frac{17}{3}

Decimal Notation

m = 3, m = - 5.66666 \dots

Solution steps

5 m^{2} + 8 m - 51 = 2 m^{2}

Move

2 m^{2}

to the left side

3 m^{2} + 8 m - 51 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 51 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 51) = 26

m_{1, 2} = \frac{- 8 \pm 26}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- 8 + 26}{2 \cdot 3}, m_{2} = \frac{- 8 - 26}{2 \cdot 3}

m = \frac{- 8 + 26}{2 \cdot 3} : 3

m = \frac{- 8 - 26}{2 \cdot 3} : - \frac{17}{3}

The solutions to the quadratic equation are:

m = 3, m = - \frac{17}{3}

- 4.9 t^{2} + t + 360 = - 4 t + 142

x^{2} + 16 x = 1555

y^{2} = 15 y

3 k^{2} + 9 k - 20 = 2 k

h^{2} + 19 h = 0

What are the solutions to the equation 5m^2+8m-51=2m^2 ?
The solutions to the equation 5m^2+8m-51=2m^2 are m=3,m=-17/3
Find the zeros of 5m^2+8m-51=2m^2
The zeros of 5m^2+8m-51=2m^2 are m=3,m=-17/3