What are the solutions to the equation roots s^2+1 ?

The solutions to the equation roots s^2+1 are s=i,s=-i

Find the zeros of roots s^2+1

The zeros of roots s^2+1 are s=i,s=-i

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roots

s^{2} + 1

s = i, s = - i

Solution steps

s^{2} + 1

The roots are the intercepts with the x-axis

(y = 0)

s^{2} + 1 = 0

Move

1

to the right side

s^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

s = - 1, s = - - 1

- 1 = i

- - 1 = - i

s = i, s = - i

5 m^{2} + 8 m - 51 = 2 m^{2}

- 4.9 t^{2} + t + 360 = - 4 t + 142

x^{2} + 16 x = 1555

y^{2} = 15 y

3 k^{2} + 9 k - 20 = 2 k

What are the solutions to the equation roots s^2+1 ?
The solutions to the equation roots s^2+1 are s=i,s=-i
Find the zeros of roots s^2+1
The zeros of roots s^2+1 are s=i,s=-i