What are the solutions to the equation roots x^2-10x+29 ?

The solutions to the equation roots x^2-10x+29 are x=5+2i,x=5-2i

Find the zeros of roots x^2-10x+29

The zeros of roots x^2-10x+29 are x=5+2i,x=5-2i

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roots

x^{2} - 10 x + 29

x = 5 + 2 i, x = 5 - 2 i

Solution steps

x^{2} - 10 x + 29

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 10 x + 29 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 29}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 29 : 4 i

x_{1, 2} = \frac{- ( - 10 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4 i}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 4 i}{2 \cdot 1}

x = \frac{- ( - 10 ) + 4 i}{2 \cdot 1} : 5 + 2 i

x = \frac{- ( - 10 ) - 4 i}{2 \cdot 1} : 5 - 2 i

The solutions to the quadratic equation are:

x = 5 + 2 i, x = 5 - 2 i

x^{2} - 10 x + 26

(x + 5)^{2} + 127 = 6

4 (x^{2} - 5) + 5 = - 3

7 x^{2} - 19 x - 6 = 0

4 x^{2} - 5 x = 6

What are the solutions to the equation roots x^2-10x+29 ?
The solutions to the equation roots x^2-10x+29 are x=5+2i,x=5-2i
Find the zeros of roots x^2-10x+29
The zeros of roots x^2-10x+29 are x=5+2i,x=5-2i