What are the solutions to the equation p^2+2p+8=0 ?

The solutions to the equation p^2+2p+8=0 are p=-1+sqrt(7)i,p=-1-sqrt(7)i

Find the zeros of p^2+2p+8=0

The zeros of p^2+2p+8=0 are p=-1+sqrt(7)i,p=-1-sqrt(7)i

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p^{2} + 2 p + 8 = 0

p = - 1 + 7 i, p = - 1 - 7 i

Solution steps

p^{2} + 2 p + 8 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 8 : 27 i

p_{1, 2} = \frac{- 2 \pm 2 7 i}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 2 + 2 7 i}{2 \cdot 1}, p_{2} = \frac{- 2 - 2 7 i}{2 \cdot 1}

p = \frac{- 2 + 2 7 i}{2 \cdot 1} : - 1 + 7 i

p = \frac{- 2 - 2 7 i}{2 \cdot 1} : - 1 - 7 i

The solutions to the quadratic equation are:

p = - 1 + 7 i, p = - 1 - 7 i

8 x - 3 x^{2} = 0

a = 2 π r^{2} + 2 π

x^{2} + 2 x - 575 = 0

3 x^{2} + 17 = - 10 x + 9

x^{2} + 6 x - 100 = 6 x

What are the solutions to the equation p^2+2p+8=0 ?
The solutions to the equation p^2+2p+8=0 are p=-1+sqrt(7)i,p=-1-sqrt(7)i
Find the zeros of p^2+2p+8=0
The zeros of p^2+2p+8=0 are p=-1+sqrt(7)i,p=-1-sqrt(7)i