What are the solutions to the equation factor 2x^2-4x=3x+4 ?

The solutions to the equation factor 2x^2-4x=3x+4 are x=-1/2 ,x=4

Find the zeros of factor 2x^2-4x=3x+4

The zeros of factor 2x^2-4x=3x+4 are x=-1/2 ,x=4

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2 x^{2} - 4 x = 3 x + 4

x = - \frac{1}{2}, x = 4

Decimal Notation

x = - 0.5, x = 4

Solution steps

2 x^{2} - 4 x = 3 x + 4

Move

4

to the left side

2 x^{2} - 4 x - 4 = 3 x

Move

3 x

to the left side

2 x^{2} - 7 x - 4 = 0

Factor

2 x^{2} - 7 x - 4 : (2 x + 1) (x - 4)

(2 x + 1) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0 or x - 4 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x - 4 = 0 : x = 4

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = 4

- x^{2} = - 64

- x^{2} = - 4 x

(4 + x)^{2} - (2 x - 1)^{2} = - 12 (5 - x)

2 (x + 1) = x^{2}

- 16 t^{2} + 184 t + 96 = 0

What are the solutions to the equation factor 2x^2-4x=3x+4 ?
The solutions to the equation factor 2x^2-4x=3x+4 are x=-1/2 ,x=4
Find the zeros of factor 2x^2-4x=3x+4
The zeros of factor 2x^2-4x=3x+4 are x=-1/2 ,x=4