What are the solutions to the equation y^2-15y-54=0 ?

The solutions to the equation y^2-15y-54=0 are y=18,y=-3

Find the zeros of y^2-15y-54=0

The zeros of y^2-15y-54=0 are y=18,y=-3

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y^{2} - 15 y - 54 = 0

y = 18, y = - 3

Solution steps

y^{2} - 15 y - 54 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot (- 54) = 21

y_{1, 2} = \frac{- ( - 15 ) \pm 21}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 15 ) + 21}{2 \cdot 1}, y_{2} = \frac{- ( - 15 ) - 21}{2 \cdot 1}

y = \frac{- ( - 15 ) + 21}{2 \cdot 1} : 18

y = \frac{- ( - 15 ) - 21}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

y = 18, y = - 3

(- 3) 1 0^{- 6} x^{2} + 0.003 x + 6 = 0

4 x^{2} + 72 x + 388 = 0

- 2 x^{2} = 32

x^{2} - 2 x + 20

25 x^{2} - 30 x + 9 = 96

What are the solutions to the equation y^2-15y-54=0 ?
The solutions to the equation y^2-15y-54=0 are y=18,y=-3
Find the zeros of y^2-15y-54=0
The zeros of y^2-15y-54=0 are y=18,y=-3