What are the solutions to the equation -2y^2+9y=8 ?

The solutions to the equation -2y^2+9y=8 are y=(9-sqrt(17))/4 ,y=(9+sqrt(17))/4

Find the zeros of -2y^2+9y=8

The zeros of -2y^2+9y=8 are y=(9-sqrt(17))/4 ,y=(9+sqrt(17))/4

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- 2 y^{2} + 9 y = 8

y = \frac{9 - 17}{4}, y = \frac{9 + 17}{4}

Decimal Notation

y = 1.21922 \dots, y = 3.28077 \dots

Solution steps

- 2 y^{2} + 9 y = 8

Move

8

to the left side

- 2 y^{2} + 9 y - 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 2 ) ( - 8 )}{2 ( - 2 )}

9^{2} - 4 (- 2) (- 8) = 17

y_{1, 2} = \frac{- 9 \pm 17}{2 ( - 2 )}

Separate the solutions

y_{1} = \frac{- 9 + 17}{2 ( - 2 )}, y_{2} = \frac{- 9 - 17}{2 ( - 2 )}

y = \frac{- 9 + 17}{2 ( - 2 )} : \frac{9 - 17}{4}

y = \frac{- 9 - 17}{2 ( - 2 )} : \frac{9 + 17}{4}

The solutions to the quadratic equation are:

y = \frac{9 - 17}{4}, y = \frac{9 + 17}{4}

- (x - 5)^{2} = 108

x^{2} - 2 x - 6

12 x^{2} - 26 x - 7 = 3 x + 1

3 x^{2} + 20 x + 16 = 6 x^{2} + 32 x + 28

(x + 5)^{2} = (5 - x)^{2} + (5 - x)^{2}

What are the solutions to the equation -2y^2+9y=8 ?
The solutions to the equation -2y^2+9y=8 are y=(9-sqrt(17))/4 ,y=(9+sqrt(17))/4
Find the zeros of -2y^2+9y=8
The zeros of -2y^2+9y=8 are y=(9-sqrt(17))/4 ,y=(9+sqrt(17))/4