What are the solutions to the equation factor x^2+3x-68=3x-4 ?

The solutions to the equation factor x^2+3x-68=3x-4 are x=-8,x=8

Find the zeros of factor x^2+3x-68=3x-4

The zeros of factor x^2+3x-68=3x-4 are x=-8,x=8

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x^{2} + 3 x - 68 = 3 x - 4

x = - 8, x = 8

Solution steps

x^{2} + 3 x - 68 = 3 x - 4

Move

4

to the left side

x^{2} + 3 x - 64 = 3 x

Move

3 x

to the left side

x^{2} - 64 = 0

Factor

x^{2} - 64 : (x + 8) (x - 8)

(x + 8) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 8 = 0 or x - 8 = 0

Solve

x + 8 = 0 : x = - 8

Solve

x - 8 = 0 : x = 8

The solutions to the quadratic equation are:

x = - 8, x = 8

6 t (t + 3) = t - 5

16 (5 - 2 x)^{2} + 33 = 42

- s^{2} - 2 s + 5 = 0

y, 40 x^{2} + 3 y^{2} - 7 x + y + 1 = 0

t^{2} + 6 t - 4 = 0

What are the solutions to the equation factor x^2+3x-68=3x-4 ?
The solutions to the equation factor x^2+3x-68=3x-4 are x=-8,x=8
Find the zeros of factor x^2+3x-68=3x-4
The zeros of factor x^2+3x-68=3x-4 are x=-8,x=8