What are the solutions to the equation 2y^2+2=9y ?

The solutions to the equation 2y^2+2=9y are y=(9+sqrt(65))/4 ,y=(9-sqrt(65))/4

Find the zeros of 2y^2+2=9y

The zeros of 2y^2+2=9y are y=(9+sqrt(65))/4 ,y=(9-sqrt(65))/4

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2 y^{2} + 2 = 9 y

y = \frac{9 + 65}{4}, y = \frac{9 - 65}{4}

Decimal Notation

y = 4.26556 \dots, y = 0.23443 \dots

Solution steps

2 y^{2} + 2 = 9 y

Move

9 y

to the left side

2 y^{2} + 2 - 9 y = 0

Write in the standard form

a x^{2} + b x + c = 0

2 y^{2} - 9 y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 \cdot 2 = 65

y_{1, 2} = \frac{- ( - 9 ) \pm 65}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- ( - 9 ) + 65}{2 \cdot 2}, y_{2} = \frac{- ( - 9 ) - 65}{2 \cdot 2}

y = \frac{- ( - 9 ) + 65}{2 \cdot 2} : \frac{9 + 65}{4}

y = \frac{- ( - 9 ) - 65}{2 \cdot 2} : \frac{9 - 65}{4}

The solutions to the quadratic equation are:

y = \frac{9 + 65}{4}, y = \frac{9 - 65}{4}

5 z^{2} - 20 z + 25 = z^{2}

3 m^{2} - 4 m - 4 = m

4 x^{2} - 12 x + 9 = 36

- 5 v^{2} + 9 v + 1 = - 6 v^{2}

3 x^{2} + 28 x + 49 = 0

What are the solutions to the equation 2y^2+2=9y ?
The solutions to the equation 2y^2+2=9y are y=(9+sqrt(65))/4 ,y=(9-sqrt(65))/4
Find the zeros of 2y^2+2=9y
The zeros of 2y^2+2=9y are y=(9+sqrt(65))/4 ,y=(9-sqrt(65))/4