What are the solutions to the equation 8z^2+18z-7=-2 ?

The solutions to the equation 8z^2+18z-7=-2 are z= 1/4 ,z=-5/2

Find the zeros of 8z^2+18z-7=-2

The zeros of 8z^2+18z-7=-2 are z= 1/4 ,z=-5/2

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8 z^{2} + 18 z - 7 = - 2

z = \frac{1}{4}, z = - \frac{5}{2}

Decimal Notation

z = 0.25, z = - 2.5

Solution steps

8 z^{2} + 18 z - 7 = - 2

Move

2

to the left side

8 z^{2} + 18 z - 5 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 8 ( - 5 )}{2 \cdot 8}

1 8^{2} - 4 \cdot 8 (- 5) = 22

z_{1, 2} = \frac{- 18 \pm 22}{2 \cdot 8}

Separate the solutions

z_{1} = \frac{- 18 + 22}{2 \cdot 8}, z_{2} = \frac{- 18 - 22}{2 \cdot 8}

z = \frac{- 18 + 22}{2 \cdot 8} : \frac{1}{4}

z = \frac{- 18 - 22}{2 \cdot 8} : - \frac{5}{2}

The solutions to the quadratic equation are:

z = \frac{1}{4}, z = - \frac{5}{2}

x^{2} + 2 x - 8 = 0

8 x^{2} - 8 = (3 x - 1)^{2}

r^{2} - 2 r + 2

4 x + x^{2} = 0

3 m^{2} + 5 m + 7 = 0

What are the solutions to the equation 8z^2+18z-7=-2 ?
The solutions to the equation 8z^2+18z-7=-2 are z= 1/4 ,z=-5/2
Find the zeros of 8z^2+18z-7=-2
The zeros of 8z^2+18z-7=-2 are z= 1/4 ,z=-5/2