What are the solutions to the equation 8x^2-8=(3x-1)^2 ?

The solutions to the equation 8x^2-8=(3x-1)^2 are x=3

Find the zeros of 8x^2-8=(3x-1)^2

The zeros of 8x^2-8=(3x-1)^2 are x=3

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8 x^{2} - 8 = (3 x - 1)^{2}

x = 3

Solution steps

8 x^{2} - 8 = (3 x - 1)^{2}

Expand

(3 x - 1)^{2} : 9 x^{2} - 6 x + 1

8 x^{2} - 8 = 9 x^{2} - 6 x + 1

Switch sides

9 x^{2} - 6 x + 1 = 8 x^{2} - 8

Move

8

to the left side

9 x^{2} - 6 x + 9 = 8 x^{2}

Move

8 x^{2}

to the left side

x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

x = 3

The solution to the quadratic equation is:

x = 3

r^{2} - 2 r + 2

4 x + x^{2} = 0

3 m^{2} + 5 m + 7 = 0

(x) = 2 x^{2} + 8 x + 11

- 5 = - \frac{1}{2} 9.8 x^{2} + 2 x

What are the solutions to the equation 8x^2-8=(3x-1)^2 ?
The solutions to the equation 8x^2-8=(3x-1)^2 are x=3
Find the zeros of 8x^2-8=(3x-1)^2
The zeros of 8x^2-8=(3x-1)^2 are x=3