What are the solutions to the equation roots r^2-2r+2 ?

The solutions to the equation roots r^2-2r+2 are r=1+i,r=1-i

Find the zeros of roots r^2-2r+2

The zeros of roots r^2-2r+2 are r=1+i,r=1-i

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roots

r^{2} - 2 r + 2

r = 1 + i, r = 1 - i

Solution steps

r^{2} - 2 r + 2

The roots are the intercepts with the x-axis

(y = 0)

r^{2} - 2 r + 2 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 2 : 2 i

r_{1, 2} = \frac{- ( - 2 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 2 ) + 2 i}{2 \cdot 1}, r_{2} = \frac{- ( - 2 ) - 2 i}{2 \cdot 1}

r = \frac{- ( - 2 ) + 2 i}{2 \cdot 1} : 1 + i

r = \frac{- ( - 2 ) - 2 i}{2 \cdot 1} : 1 - i

The solutions to the quadratic equation are:

r = 1 + i, r = 1 - i

4 x + x^{2} = 0

3 m^{2} + 5 m + 7 = 0

(x) = 2 x^{2} + 8 x + 11

- 5 = - \frac{1}{2} 9.8 x^{2} + 2 x

x, z^{2} = x^{2} y + 4.02

What are the solutions to the equation roots r^2-2r+2 ?
The solutions to the equation roots r^2-2r+2 are r=1+i,r=1-i
Find the zeros of roots r^2-2r+2
The zeros of roots r^2-2r+2 are r=1+i,r=1-i