What are the solutions to the equation -12=-3(x-3)^2 ?

The solutions to the equation -12=-3(x-3)^2 are x=5,x=1

Find the zeros of -12=-3(x-3)^2

The zeros of -12=-3(x-3)^2 are x=5,x=1

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- 12 = - 3 (x - 3)^{2}

x = 5, x = 1

Solution steps

- 12 = - 3 (x - 3)^{2}

Switch sides

- 3 (x - 3)^{2} = - 12

Divide both sides by

- 3

(x - 3)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 4 : x = 5

Solve

x - 3 = - 4 : x = 1

The solutions to the quadratic equation are:

x = 5, x = 1

x^{2} - x + \frac{6}{25} = 0

\frac{1}{7} p^{2} = \frac{5}{7} p^{2} - 20

2 x^{2} + 12 x - 3

4.9 t^{2} + 6 t + 2 = 0

x^{2} + 4 x - 12

What are the solutions to the equation -12=-3(x-3)^2 ?
The solutions to the equation -12=-3(x-3)^2 are x=5,x=1
Find the zeros of -12=-3(x-3)^2
The zeros of -12=-3(x-3)^2 are x=5,x=1