What are the solutions to the equation x^2+3=1 ?

The solutions to the equation x^2+3=1 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of x^2+3=1

The zeros of x^2+3=1 are x=sqrt(2)i,x=-sqrt(2)i

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x^{2} + 3 = 1

x = 2 i, x = - 2 i

Solution steps

x^{2} + 3 = 1

Move

3

to the right side

x^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 2, x = - - 2

- 2 = 2 i

- - 2 = - 2 i

x = 2 i, x = - 2 i

x^{2} - 4 x - 20 = - 5 x

4 (x - 2)^{2} = 5

4 (x - 2)^{2} = 9

x^{2} - 2 x + 8 = 4 x

y, x^{2} y^{2} - 2 x^{2} y + x^{2} - 2 x + 1 = 0

What are the solutions to the equation x^2+3=1 ?
The solutions to the equation x^2+3=1 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of x^2+3=1
The zeros of x^2+3=1 are x=sqrt(2)i,x=-sqrt(2)i