What are the solutions to the equation solvefor x,x^2+2x+1-m^2=0 ?

The solutions to the equation solvefor x,x^2+2x+1-m^2=0 are x=-m-1,x=m-1

Find the zeros of solvefor x,x^2+2x+1-m^2=0

The zeros of solvefor x,x^2+2x+1-m^2=0 are x=-m-1,x=m-1

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x, x^{2} + 2 x + 1 - m^{2} = 0

x = - m - 1, x = m - 1

Solution steps

x^{2} + 2 x + 1 - m^{2} = 0

Factor

x^{2} + 2 x + 1 - m^{2} : (x + m + 1) (x - m + 1)

(x + m + 1) (x - m + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + m + 1 = 0 or x - m + 1 = 0

Solve

x + m + 1 = 0 : x = - m - 1

Solve

x - m + 1 = 0 : x = m - 1

The solutions to the quadratic equation are:

x = - m - 1, x = m - 1

r^{2} = - 96

x^{2} - 8 x + 65 = 0

x^{2} - 0.2 x - 4.85 = 0

x^{2} = \frac{2}{3} x + \frac{16}{3}

y, x^{2} + y^{2} + 2 x y - 7 x - 6 y + 10 = 0

What are the solutions to the equation solvefor x,x^2+2x+1-m^2=0 ?
The solutions to the equation solvefor x,x^2+2x+1-m^2=0 are x=-m-1,x=m-1
Find the zeros of solvefor x,x^2+2x+1-m^2=0
The zeros of solvefor x,x^2+2x+1-m^2=0 are x=-m-1,x=m-1