What are the solutions to the equation x^2-10x+89=0 ?

The solutions to the equation x^2-10x+89=0 are x=5+8i,x=5-8i

Find the zeros of x^2-10x+89=0

The zeros of x^2-10x+89=0 are x=5+8i,x=5-8i

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x^{2} - 10 x + 89 = 0

x = 5 + 8 i, x = 5 - 8 i

Solution steps

x^{2} - 10 x + 89 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 89}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 89 : 16 i

x_{1, 2} = \frac{- ( - 10 ) \pm 16 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 16 i}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 16 i}{2 \cdot 1}

x = \frac{- ( - 10 ) + 16 i}{2 \cdot 1} : 5 + 8 i

x = \frac{- ( - 10 ) - 16 i}{2 \cdot 1} : 5 - 8 i

The solutions to the quadratic equation are:

x = 5 + 8 i, x = 5 - 8 i

8 w^{2} - 8 w + 2 = 0

y, x^{2} + x y + 2 y^{2} = 1

413 = 9 x^{2} + 2 x + 1

y, 1 = 3 x + 2 x^{2} y^{2}

- 150 = \frac{1}{2} (- 0.98) x^{2}

What are the solutions to the equation x^2-10x+89=0 ?
The solutions to the equation x^2-10x+89=0 are x=5+8i,x=5-8i
Find the zeros of x^2-10x+89=0
The zeros of x^2-10x+89=0 are x=5+8i,x=5-8i