What are the solutions to the equation 5x^2-21x+11=-4x ?

The solutions to the equation 5x^2-21x+11=-4x are x=(17+sqrt(69))/(10),x=(17-sqrt(69))/(10)

Find the zeros of 5x^2-21x+11=-4x

The zeros of 5x^2-21x+11=-4x are x=(17+sqrt(69))/(10),x=(17-sqrt(69))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} - 21 x + 11 = - 4 x

x = \frac{17 + 69}{10}, x = \frac{17 - 69}{10}

Decimal Notation

x = 2.53066 \dots, x = 0.86933 \dots

Solution steps

5 x^{2} - 21 x + 11 = - 4 x

Move

4 x

to the left side

5 x^{2} - 17 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 5 \cdot 11}{2 \cdot 5}

(- 17)^{2} - 4 \cdot 5 \cdot 11 = 69

x_{1, 2} = \frac{- ( - 17 ) \pm 69}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 69}{2 \cdot 5}, x_{2} = \frac{- ( - 17 ) - 69}{2 \cdot 5}

x = \frac{- ( - 17 ) + 69}{2 \cdot 5} : \frac{17 + 69}{10}

x = \frac{- ( - 17 ) - 69}{2 \cdot 5} : \frac{17 - 69}{10}

The solutions to the quadratic equation are:

x = \frac{17 + 69}{10}, x = \frac{17 - 69}{10}

7 x^{2} + 28 x = - 2

4^{2} = 2.25 x^{2} + x^{2}

x^{2} - x - 12

- 5 (2 x - 20) (15 + 5 x) = 0

4 x^{2} - 2 x = - 5

What are the solutions to the equation 5x^2-21x+11=-4x ?
The solutions to the equation 5x^2-21x+11=-4x are x=(17+sqrt(69))/(10),x=(17-sqrt(69))/(10)
Find the zeros of 5x^2-21x+11=-4x
The zeros of 5x^2-21x+11=-4x are x=(17+sqrt(69))/(10),x=(17-sqrt(69))/(10)