What are the solutions to the equation 4+9x-3x^2=2-x ?

The solutions to the equation 4+9x-3x^2=2-x are x=-(-5+sqrt(31))/3 ,x=(5+sqrt(31))/3

Find the zeros of 4+9x-3x^2=2-x

The zeros of 4+9x-3x^2=2-x are x=-(-5+sqrt(31))/3 ,x=(5+sqrt(31))/3

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4 + 9 x - 3 x^{2} = 2 - x

x = - \frac{- 5 + 31}{3}, x = \frac{5 + 31}{3}

Decimal Notation

x = - 0.18925 \dots, x = 3.52258 \dots

Solution steps

4 + 9 x - 3 x^{2} = 2 - x

Move

x

to the left side

- 3 x^{2} + 10 x + 4 = 2

Move

2

to the left side

- 3 x^{2} + 10 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 3 ) \cdot 2}{2 ( - 3 )}

1 0^{2} - 4 (- 3) \cdot 2 = 231

x_{1, 2} = \frac{- 10 \pm 2 31}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 10 + 2 31}{2 ( - 3 )}, x_{2} = \frac{- 10 - 2 31}{2 ( - 3 )}

x = \frac{- 10 + 2 31}{2 ( - 3 )} : - \frac{- 5 + 31}{3}

x = \frac{- 10 - 2 31}{2 ( - 3 )} : \frac{5 + 31}{3}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 31}{3}, x = \frac{5 + 31}{3}

6 b^{2} - 7 b - 21 = - 1

5 (u + 6) (- u + 3) = 0

7 t^{2} - 18 t = 14 + 10 t

3 x^{2} + 8 x - 3 = 0

6 x^{2} - 12 x + 9 = 0

What are the solutions to the equation 4+9x-3x^2=2-x ?
The solutions to the equation 4+9x-3x^2=2-x are x=-(-5+sqrt(31))/3 ,x=(5+sqrt(31))/3
Find the zeros of 4+9x-3x^2=2-x
The zeros of 4+9x-3x^2=2-x are x=-(-5+sqrt(31))/3 ,x=(5+sqrt(31))/3