What are the solutions to the equation 5(u+6)(-u+3)=0 ?

The solutions to the equation 5(u+6)(-u+3)=0 are u=-6,u=3

Find the zeros of 5(u+6)(-u+3)=0

The zeros of 5(u+6)(-u+3)=0 are u=-6,u=3

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5 (u + 6) (- u + 3) = 0

u = - 6, u = 3

Solution steps

5 (u + 6) (- u + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

u + 6 = 0 or - u + 3 = 0

Solve

u + 6 = 0 : u = - 6

Solve

- u + 3 = 0 : u = 3

The solutions to the quadratic equation are:

u = - 6, u = 3

7 t^{2} - 18 t = 14 + 10 t

3 x^{2} + 8 x - 3 = 0

6 x^{2} - 12 x + 9 = 0

3 x^{2} + 11 x - 15 = 0

7 q^{2} + 6 q + 3 = 6 q^{2}

What are the solutions to the equation 5(u+6)(-u+3)=0 ?
The solutions to the equation 5(u+6)(-u+3)=0 are u=-6,u=3
Find the zeros of 5(u+6)(-u+3)=0
The zeros of 5(u+6)(-u+3)=0 are u=-6,u=3