What are the solutions to the equation x^2-10x+36=0 ?

The solutions to the equation x^2-10x+36=0 are x=5+sqrt(11)i,x=5-sqrt(11)i

Find the zeros of x^2-10x+36=0

The zeros of x^2-10x+36=0 are x=5+sqrt(11)i,x=5-sqrt(11)i

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x^{2} - 10 x + 36 = 0

x = 5 + 11 i, x = 5 - 11 i

Solution steps

x^{2} - 10 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 36 : 211 i

x_{1, 2} = \frac{- ( - 10 ) \pm 2 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 11 i}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 11 i}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 11 i}{2 \cdot 1} : 5 + 11 i

x = \frac{- ( - 10 ) - 2 11 i}{2 \cdot 1} : 5 - 11 i

The solutions to the quadratic equation are:

x = 5 + 11 i, x = 5 - 11 i

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What are the solutions to the equation x^2-10x+36=0 ?
The solutions to the equation x^2-10x+36=0 are x=5+sqrt(11)i,x=5-sqrt(11)i
Find the zeros of x^2-10x+36=0
The zeros of x^2-10x+36=0 are x=5+sqrt(11)i,x=5-sqrt(11)i