What are the solutions to the equation 2700=700+900x-100x^2 ?

The solutions to the equation 2700=700+900x-100x^2 are x=4,x=5

Find the zeros of 2700=700+900x-100x^2

The zeros of 2700=700+900x-100x^2 are x=4,x=5

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2700 = 700 + 900 x - 100 x^{2}

x = 4, x = 5

Solution steps

2700 = 700 + 900 x - 100 x^{2}

Switch sides

700 + 900 x - 100 x^{2} = 2700

Move

2700

to the left side

- 100 x^{2} + 900 x - 2000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 900 \pm 90 0 ^{2} - 4 ( - 100 ) ( - 2000 )}{2 ( - 100 )}

90 0^{2} - 4 (- 100) (- 2000) = 100

x_{1, 2} = \frac{- 900 \pm 100}{2 ( - 100 )}

Separate the solutions

x_{1} = \frac{- 900 + 100}{2 ( - 100 )}, x_{2} = \frac{- 900 - 100}{2 ( - 100 )}

x = \frac{- 900 + 100}{2 ( - 100 )} : 4

x = \frac{- 900 - 100}{2 ( - 100 )} : 5

The solutions to the quadratic equation are:

x = 4, x = 5

x^{2} - 4 x + 7

6 0^{2} - 4 2^{2} = x^{2}

3 r^{2} + 4 r + 5 = 0

0 = 9 x^{2} + 3 x - 2

x^{2} + 8 x + 41

What are the solutions to the equation 2700=700+900x-100x^2 ?
The solutions to the equation 2700=700+900x-100x^2 are x=4,x=5
Find the zeros of 2700=700+900x-100x^2
The zeros of 2700=700+900x-100x^2 are x=4,x=5