What are the solutions to the equation a^2+5a+25=0 ?

The solutions to the equation a^2+5a+25=0 are a=-5/2+i(5sqrt(3))/2 ,a=-5/2-i(5sqrt(3))/2

Find the zeros of a^2+5a+25=0

The zeros of a^2+5a+25=0 are a=-5/2+i(5sqrt(3))/2 ,a=-5/2-i(5sqrt(3))/2

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a^{2} + 5 a + 25 = 0

a = - \frac{5}{2} + i \frac{5 3}{2}, a = - \frac{5}{2} - i \frac{5 3}{2}

Solution steps

a^{2} + 5 a + 25 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

5^{2} - 4 \cdot 1 \cdot 25 : 53 i

a_{1, 2} = \frac{- 5 \pm 5 3 i}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 5 + 5 3 i}{2 \cdot 1}, a_{2} = \frac{- 5 - 5 3 i}{2 \cdot 1}

a = \frac{- 5 + 5 3 i}{2 \cdot 1} : - \frac{5}{2} + i \frac{5 3}{2}

a = \frac{- 5 - 5 3 i}{2 \cdot 1} : - \frac{5}{2} - i \frac{5 3}{2}

The solutions to the quadratic equation are:

a = - \frac{5}{2} + i \frac{5 3}{2}, a = - \frac{5}{2} - i \frac{5 3}{2}

v, m g h = \frac{1}{2} m v^{2}

2700 = 700 + 900 x - 100 x^{2}

x^{2} - 4 x + 7

6 0^{2} - 4 2^{2} = x^{2}

3 r^{2} + 4 r + 5 = 0

What are the solutions to the equation a^2+5a+25=0 ?
The solutions to the equation a^2+5a+25=0 are a=-5/2+i(5sqrt(3))/2 ,a=-5/2-i(5sqrt(3))/2
Find the zeros of a^2+5a+25=0
The zeros of a^2+5a+25=0 are a=-5/2+i(5sqrt(3))/2 ,a=-5/2-i(5sqrt(3))/2