What are the solutions to the equation 40x^2-13x+1=0 ?

The solutions to the equation 40x^2-13x+1=0 are x= 1/5 ,x= 1/8

Find the zeros of 40x^2-13x+1=0

The zeros of 40x^2-13x+1=0 are x= 1/5 ,x= 1/8

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40 x^{2} - 13 x + 1 = 0

x = \frac{1}{5}, x = \frac{1}{8}

Decimal Notation

x = 0.2, x = 0.125

Solution steps

40 x^{2} - 13 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 40 \cdot 1}{2 \cdot 40}

(- 13)^{2} - 4 \cdot 40 \cdot 1 = 3

x_{1, 2} = \frac{- ( - 13 ) \pm 3}{2 \cdot 40}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 3}{2 \cdot 40}, x_{2} = \frac{- ( - 13 ) - 3}{2 \cdot 40}

x = \frac{- ( - 13 ) + 3}{2 \cdot 40} : \frac{1}{5}

x = \frac{- ( - 13 ) - 3}{2 \cdot 40} : \frac{1}{8}

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = \frac{1}{8}

25 (5 x - 3)^{2} + 6 = 22

0.7 t^{2} = 14 t

x, m x^{2} + 5 x + 2 = 0

4 x^{2} + 83 = - 36 x

8 x^{2} - 40 x + 32 = 0

What are the solutions to the equation 40x^2-13x+1=0 ?
The solutions to the equation 40x^2-13x+1=0 are x= 1/5 ,x= 1/8
Find the zeros of 40x^2-13x+1=0
The zeros of 40x^2-13x+1=0 are x= 1/5 ,x= 1/8