What are the solutions to the equation 5x^2+5x-3/4 =0 ?

The solutions to the equation 5x^2+5x-3/4 =0 are x=(-5+2sqrt(10))/(10),x=-(5+2sqrt(10))/(10)

Find the zeros of 5x^2+5x-3/4 =0

The zeros of 5x^2+5x-3/4 =0 are x=(-5+2sqrt(10))/(10),x=-(5+2sqrt(10))/(10)

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5 x^{2} + 5 x - \frac{3}{4} = 0

x = \frac{- 5 + 2 10}{10}, x = - \frac{5 + 2 10}{10}

Decimal Notation

x = 0.13245 \dots, x = - 1.13245 \dots

Solution steps

5 x^{2} + 5 x - \frac{3}{4} = 0

Multiply both sides by

4

20 x^{2} + 20 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 20 ( - 3 )}{2 \cdot 20}

2 0^{2} - 4 \cdot 20 (- 3) = 810

x_{1, 2} = \frac{- 20 \pm 8 10}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- 20 + 8 10}{2 \cdot 20}, x_{2} = \frac{- 20 - 8 10}{2 \cdot 20}

x = \frac{- 20 + 8 10}{2 \cdot 20} : \frac{- 5 + 2 10}{10}

x = \frac{- 20 - 8 10}{2 \cdot 20} : - \frac{5 + 2 10}{10}

The solutions to the quadratic equation are:

x = \frac{- 5 + 2 10}{10}, x = - \frac{5 + 2 10}{10}

3 x^{2} + 12 x = 7 x + 2

(x - 1)^{2}

s^{2} - 6 s + 25

x^{2} - 18 x + 60 = - 21

9 x^{2} - 48 x + 65 = 0

What are the solutions to the equation 5x^2+5x-3/4 =0 ?
The solutions to the equation 5x^2+5x-3/4 =0 are x=(-5+2sqrt(10))/(10),x=-(5+2sqrt(10))/(10)
Find the zeros of 5x^2+5x-3/4 =0
The zeros of 5x^2+5x-3/4 =0 are x=(-5+2sqrt(10))/(10),x=-(5+2sqrt(10))/(10)