What are the solutions to the equation factor 3x^2+12x=7x+2 ?

The solutions to the equation factor 3x^2+12x=7x+2 are x= 1/3 ,x=-2

Find the zeros of factor 3x^2+12x=7x+2

The zeros of factor 3x^2+12x=7x+2 are x= 1/3 ,x=-2

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3 x^{2} + 12 x = 7 x + 2

x = \frac{1}{3}, x = - 2

Decimal Notation

x = 0.33333 \dots, x = - 2

Solution steps

3 x^{2} + 12 x = 7 x + 2

Move

2

to the left side

3 x^{2} + 12 x - 2 = 7 x

Move

7 x

to the left side

3 x^{2} + 5 x - 2 = 0

Factor

3 x^{2} + 5 x - 2 : (3 x - 1) (x + 2)

(3 x - 1) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 1 = 0 or x + 2 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 2

(x - 1)^{2}

s^{2} - 6 s + 25

x^{2} - 18 x + 60 = - 21

9 x^{2} - 48 x + 65 = 0

2 W^{2} - 5 W - 52 = 0

What are the solutions to the equation factor 3x^2+12x=7x+2 ?
The solutions to the equation factor 3x^2+12x=7x+2 are x= 1/3 ,x=-2
Find the zeros of factor 3x^2+12x=7x+2
The zeros of factor 3x^2+12x=7x+2 are x= 1/3 ,x=-2