What are the solutions to the equation factor 3x^2-5=-5x-3 ?

The solutions to the equation factor 3x^2-5=-5x-3 are x= 1/3 ,x=-2

Find the zeros of factor 3x^2-5=-5x-3

The zeros of factor 3x^2-5=-5x-3 are x= 1/3 ,x=-2

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3 x^{2} - 5 = - 5 x - 3

x = \frac{1}{3}, x = - 2

Decimal Notation

x = 0.33333 \dots, x = - 2

Solution steps

3 x^{2} - 5 = - 5 x - 3

Move

3

to the left side

3 x^{2} - 2 = - 5 x

Move

5 x

to the left side

3 x^{2} - 2 + 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 5 x - 2 = 0

Factor

3 x^{2} + 5 x - 2 : (3 x - 1) (x + 2)

(3 x - 1) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 1 = 0 or x + 2 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 2

x^{2} + 2 x - 4

5 x^{2} = 3

5 t^{2} + 7 t = 9

x^{2} - 4 x + 125 = 0

10 w^{2} - 15 w - 9 = 18 - 6 w + 4 w^{2}

What are the solutions to the equation factor 3x^2-5=-5x-3 ?
The solutions to the equation factor 3x^2-5=-5x-3 are x= 1/3 ,x=-2
Find the zeros of factor 3x^2-5=-5x-3
The zeros of factor 3x^2-5=-5x-3 are x= 1/3 ,x=-2