What are the solutions to the equation 5t^2+7t=9 ?

The solutions to the equation 5t^2+7t=9 are t=(-7+sqrt(229))/(10),t=(-7-sqrt(229))/(10)

Find the zeros of 5t^2+7t=9

The zeros of 5t^2+7t=9 are t=(-7+sqrt(229))/(10),t=(-7-sqrt(229))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 t^{2} + 7 t = 9

t = \frac{- 7 + 229}{10}, t = \frac{- 7 - 229}{10}

Decimal Notation

t = 0.81327 \dots, t = - 2.21327 \dots

Solution steps

5 t^{2} + 7 t = 9

Move

9

to the left side

5 t^{2} + 7 t - 9 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 ( - 9 )}{2 \cdot 5}

7^{2} - 4 \cdot 5 (- 9) = 229

t_{1, 2} = \frac{- 7 \pm 229}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- 7 + 229}{2 \cdot 5}, t_{2} = \frac{- 7 - 229}{2 \cdot 5}

t = \frac{- 7 + 229}{2 \cdot 5} : \frac{- 7 + 229}{10}

t = \frac{- 7 - 229}{2 \cdot 5} : \frac{- 7 - 229}{10}

The solutions to the quadratic equation are:

t = \frac{- 7 + 229}{10}, t = \frac{- 7 - 229}{10}

x^{2} - 4 x + 125 = 0

10 w^{2} - 15 w - 9 = 18 - 6 w + 4 w^{2}

3 x^{2} - 2 = - x

y, x y + 2 x + 3 x^{2} = 4

- 2 x^{2} - 4 x + 6

What are the solutions to the equation 5t^2+7t=9 ?
The solutions to the equation 5t^2+7t=9 are t=(-7+sqrt(229))/(10),t=(-7-sqrt(229))/(10)
Find the zeros of 5t^2+7t=9
The zeros of 5t^2+7t=9 are t=(-7+sqrt(229))/(10),t=(-7-sqrt(229))/(10)