What are the solutions to the equation roots x^2+3x-5 ?

The solutions to the equation roots x^2+3x-5 are x=(-3+sqrt(29))/2 ,x=(-3-sqrt(29))/2

Find the zeros of roots x^2+3x-5

The zeros of roots x^2+3x-5 are x=(-3+sqrt(29))/2 ,x=(-3-sqrt(29))/2

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roots

x^{2} + 3 x - 5

x = \frac{- 3 + 29}{2}, x = \frac{- 3 - 29}{2}

Solution steps

x^{2} + 3 x - 5

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 5) = 29

x_{1, 2} = \frac{- 3 \pm 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 29}{2 \cdot 1}, x_{2} = \frac{- 3 - 29}{2 \cdot 1}

x = \frac{- 3 + 29}{2 \cdot 1} : \frac{- 3 + 29}{2}

x = \frac{- 3 - 29}{2 \cdot 1} : \frac{- 3 - 29}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 29}{2}, x = \frac{- 3 - 29}{2}

x^{2} + 3 x + 9

- 16 = x^{2} - 10 x

0 = 3 x^{2} + 4 x - 4

x^{2} + x a + a^{2}

- x^{2} - 0 x + 16 = 0

What are the solutions to the equation roots x^2+3x-5 ?
The solutions to the equation roots x^2+3x-5 are x=(-3+sqrt(29))/2 ,x=(-3-sqrt(29))/2
Find the zeros of roots x^2+3x-5
The zeros of roots x^2+3x-5 are x=(-3+sqrt(29))/2 ,x=(-3-sqrt(29))/2